How to find a row of a large matrix
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I have a 64 by 3 matrix in which each row is a combination of 1, 2, 3, and 4. I want to find row: 1 3 3, and I used the "find" command for this, but it didn't work. Any help would be appreciated!
M = 4;
N = 3;
[X{N:-1:1}] = ndgrid(1:M);
X = reshape(cat(N+1,X{:}),[],N)
find(X==[1 3 3])
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Accepted Answer
Bruno Luong
on 2 Aug 2020
Edited: Bruno Luong
on 3 Aug 2020
It seems you run old MATLAB version without auto-expansion capability.
This will work for any version:
row = find(ismember(X,[1 3 3],'rows'))
Check
X(row,:)
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