Histogram with log Bin width

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I have a single column vector with values ranging from 0 to about 400 000.
I need to make a histogram from this data, which has a logarithmically changing bin size.
The height values in each bin should also be divided with the corresponding bins width.
How can this be done?
Advice would be appreciated,
Thanks

Accepted Answer

Sean de Wolski
Sean de Wolski on 3 Aug 2020
x = rand(1,10000)*100000;
bins = 10.^(0:5);
histogram(x, bins);
set(gca, "XScale", "log")
  1 Comment
Markus Similä
Markus Similä on 4 Aug 2020
Thanks!
This sort of works. But does it divide the values by the width of each bin?

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More Answers (1)

Markus Similä
Markus Similä on 6 Aug 2020
Edited: Markus Similä on 6 Aug 2020
edges = 10.^(1:0.01:6);
[N,edges] = histcounts(x,edges,'Normalization','countdensity');
g = histogram('BinEdges',edges,'BinCounts',N);
set(gca, "Xscale", "log")
set(gca, "YScale", "log")
Allright, I'm going to answer my own question.
x is your data.
'countdensity' normalizes the data exactly how you want.
Make sure that the histogram command doesn't bin your data anymore,
as you have done it already in histcounts. :D

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