Problem with how to select the best result from a loop calculation

Dear All,

Thanks for your time.

I am currently writting a code. I would like to obtain the best solution after running a loop and then obtain the corresponding variables used. I will show a sample code such as:

for i=1:2
  a(1)=2
  a(2)=3
  c=a.*3
end
b=min(c)
d=a(i)

The correct answer is b=6 and d=a(1).However, I can either get b=6 but d=a(3) or b=9 and d=a(2).

Could somebody help me with this please? Thank you very much.

Zhe Li

[EDITED, Jan, code formatted]

[Jan]

The contents of the FOR loop does not depend on the loop counter "i". So why do you use a loop? How can "d=a(3)" happen, when you define only a(1) and a(2)?

[zhe li]

Dear Jan,

Thanks for sending me the comments.

I only used this as an example. The actual code I am writting involved calling other functions instead of a(1) and a(2). This is the reason that I used 'for loop'. d=a(3) is not going happen as far as I am concerned, as the example showing, I would only expect two sets of calculation done.

Thanks again,

Zhe Li

Answer 1

[José-Luis]

 the_best = bitmax; %largest possible value, Inf would work as well

for ii = 1:1000
    your_new_min = %however you get it
    if (your_new_min < the_best)
        the_best = your_new_min;
        b_best = %whatever the current value of b is
        d_best = %whatever the current value of d is
    end 
end

[zhe li]

Hi Jose-luis,

Thanks so much for the answer. I think I got it working in a hard way, but I will definetely try your solution, it looks a lot smarter than mine.

Thanks again,

Zhe Li

[José-Luis]

My pleasure, please don't forget to accept an answer if it helps you.