for loop - how to obtain a list of solutions
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Sergio Orasch
on 9 Sep 2020
Answered: Walter Roberson
on 9 Sep 2020
hello,
I would like to show you my problem in MATLAB. In order to solve an equation with an variable input, I created a for loop in order to obtain a list with all solutions. The for loop should run n times. Everytime it starts s0_y should be changed (add +100 to the current value). The output v_safe should be safed in a seperate list for further calculations. How do I run the loop n times? How do I increase s0_y by 100? How do I save v_safe in a seperate list? Thank you very much for any support.
If I run the program I get following error code.
Index exceeds the number of array elements (1).
s0_y = y_k(k)
Command Window results:
n = 7
s0_y = 1000
s0_y = 1000
s0_y = 1100
s0_y = 1100
s0_y = 1300
s0_y = 1300
s0_y = 1600
s0_y = 1600
code:
v0_x = 100; %m/s
s0_x = -5000; %m
a_x = 0; %m/s^2
syms v0_y;
s0_y = 1000;
a_y = 0; %m/s^2
h_B = 1500; %m
S_H = 100; %m
h_BS = h_B+S_H;
n = length(s0_y:100:h_BS)
for k = 1:n
y_k = [s0_y:100:h_BS];
s0_y = y_k(k)
s0_y
syms t;
s_x = s0_x+v0_x*t+(a_x*t*t)/2 == 0;
t_col = solve(s_x,t);
s_sol = s0_y+v0_y*t_col+(a_y*t_col*t_col)/2-h_BS;
v_safe = solve(s_sol,v0_y);
end
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Accepted Answer
Walter Roberson
on 9 Sep 2020
y_k = [s0_y:100:h_BS];
for k = 1:n
s0_y = y_k(k)
s0_y
syms t;
s_x = s0_x+v0_x*t+(a_x*t*t)/2 == 0;
t_col = solve(s_x,t);
s_sol = s0_y+v0_y*t_col+(a_y*t_col*t_col)/2-h_BS;
v_safe(k) = solve(s_sol,v0_y);
end
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