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how to solve this system of equation? (not sure what it's called/)

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Waritwong Sukprasongdee
Waritwong Sukprasongdee on 10 Sep 2020
Commented: Dana on 10 Sep 2020
syms f0 fa n t
>> eqn1 = fo*cosd(t)+fa*sind(15)==0;
>> eqn2 = fo*sind(t)+n-fa*cosd(15)==0;
>> eqn3 = n*1.2-fa*sind(15)*2.4*sind(30)-fa*cosd(15)*2.4*cosd(30)==0;
>> eqn4= -n*(2.4+2.4*cosd(30))-fo*sind(t)*2.4*sind(30)+fo*cosd(t)*2.4*cosd(30)==0;

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Answers (1)

Dana
Dana on 10 Sep 2020
syms fo fa n t % note you had f0 instead of fo here in your original post
eqn1 = fo*cosd(t)+fa*sind(15)==0;
eqn2 = fo*sind(t)+n-fa*cosd(15)==0;
eqn3 = n*1.2-fa*sind(15)*2.4*sind(30)-fa*cosd(15)*2.4*cosd(30)==0;
eqn4= -n*(2.4+2.4*cosd(30))-fo*sind(t)*2.4*sind(30)+fo*cosd(t)*2.4*cosd(30)==0;
S = solve(eqn1,eqn2,eqn3,eqn4,fo,fa,n,t);
Though it appears the solutions are pretty trivial: everything is zero except for t, which can be either 0 or 180 (in both of these cases, sind(t)=0).

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