Counting every other number in a list

Howdy.

I have a matrix

mylist = [1:10]

I need to count every other number in this matrix

I can't use the odd or even distinguishing tests such as...

for i = 1:length(mylist)

if rem(mylist(i),2) ~= 0;

eo_total = eo_total + 1

end

end

Because this only counts the odd numbers in my for loop. So if I had a matrix

mylist(2) = [ 2 4 6 8 10]

eo_total = 0 instead of 2

any ideas?

Answer 1

[the cyclist]

I'm not sure what you mean by "count" them, but the following vector will store every other element from mylist, starting with the first one:

out = mylist(1:2:end)

[Nathaniel Wolff]

by count I mean that litterally. I want to count every other other digit in my matrix.

for instance

[1 2 3 4 5]

Ideally i would have a function that would output 2. Becuause if I start at 1, not counting itself, the next other number would be 3 then the last is 5. But I can't have it be odd or even because this list might be something disproportionalty even or odd.

thank you for the code, I can just use a length(out) to count the number of digits in this new matrix.

that's actually much simpler then what I was trying to do with for loops

[the cyclist]

Oh. Then it's probably more efficient to do

ceil(numel(mylist)/2)

Then you don't need to create a second vector.