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Using for loop to extract data from a matrix

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I am trying to etract certain data from a matrix into a single row vector with the length of the vector depending on the number of elements in the atrix.
So for example I extracted successfully the element numbers that represents one building component with the following code:
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
%Assign Elements to part Cavity
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
groupc=strfind(aName,'Cavity');
tf= cellfun('isempty',groupc); %tf gives 1, if cell contains []
for i=1:length(tf) %converts [] to 0
if tf(i)==1
groupc(i)={0};
end
end
groupc=cell2mat(groupc);
combic= [aElements,groupc]; %aElements is defined as a cell array containing all existing Element number of the whole building model
cavity= ones(length(aElements),1);
n=1;
for j=1:length(aElements)
if combic(j,groupc(j)==1)
cavity(n)=combic(j,1);
n=n+1;
end
end
The result "cavity" I get is attached to this question. What I want is the loop to stop, before filling out the rows with "1" and give out a vector that has the length of the number of elements that belong to one part (in this case to the part cavity). How can I do that?

  2 Comments

madhan ravi
madhan ravi on 3 Oct 2020
Your question isn't clear, what ones? You already preallocate cavity with ones? Instead of posting a random picture why not illustrate with a short example with the desired result?
cell_array = {[]; 4646; 3883; 0}
desired_result = % ??
Brendan Görres
Brendan Görres on 3 Oct 2020
the problem was the preallocation. I missed that.

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Accepted Answer

Abdolkarim Mohammadi-Balani
The break statement terminates the for loop:
if j > numel(cavity)
break
end

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