# Compare 2 arrays using for loop and if statement

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I want to compare enteries of 2 arrays and if they follow the condition, store the value at the same index in a separate array.

The following code is giving me an error. Please let me know what else can I use?

I want to return the 2D array M_filter_1

M =[1 2 3 ; 8 9 0];

e = 2;

M_filter_1=[[]];

n = size(M,2)

m = size(M,1)

A =[1 2 3 4 5 6 7 8 9 0];

for k = 1:1:size(A,2)

for i= 1:1:m

for j = 1:1:n

if (M(i,j)> A(k) - e) & (M (i,j)< A(k)+ e)

M_filter_1(i,j) = M(i,j);

else

M_filter_1(i,j)= 0 ;

end

end

end

end

##### 16 Comments

Walter Roberson
on 18 Oct 2020

### Answers (1)

Asad (Mehrzad) Khoddam
on 18 Oct 2020

M =[1 2 3 ; 8 9 0];

e = 2;

m = size(M,1);

n = size(M,2);

M_filter_1 = zeros(size(M));

A =[1 2 3 4 5 6 7 8 9 0];

for a = A

for i= 1:1:m

for j = 1:1:n

if (M(i,j)> a - e) && (M (i,j)< a + e)

M_filter_1(i,j) = M(i,j);

end

end

end

end

##### 0 Comments

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