Obtain max output value Simulink

Hello, I have a little doubt, someone could tell me how to get the maximum value of the output (curve shown in blue on the oscilloscope)

Thank you so much.

Answer 1

[Ameer Hamza]

max block is not suitable for saving the maximum value. See the example in the attached file (Saved in R2020b).

[Alejandro Fernández]

Wow, thank you so much! And maybe you know how can I implement this function in another block?

function Ts = fnc(data,t)
idx = abs(data-data(end)) < 0.05 * data(end);
idx = find(idx == 1);
Ts = t(idx(1));
end

Being the variable data the information obtained at the output and t the time vector that the test is performed.

What the function should do is to give the first instant of time that enters within a margin of +-5% of the value of the output

[Ameer Hamza]

data(end) will not be available until simulation is completed. You can not use it in the test. Note that Simulink will not input a vector 'data'. At each iteration, 'data' will be a scalar number. Since you already now that data(end) is 1, so directly use it. Something like this

function Ts = fnc(data,t)

persistent flag
persistent T
if isempty(flag)
    flag = 1;
    T = 0;
end

if flag && (abs(data-1) < 0.05 * 1)
    flag = false;
    T = t;
end

Ts = T;

However, it will note the time when the output is rising, not when it is settling.

[Alejandro Fernández]

And where can I get the t-value of what I have in simulink? I tried with a Clock but I don't know if it's correct..

[Ameer Hamza]

No, clock is the correct block to use here. I should be giving the correct time values.