How to find longest sequennce within a character array?
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lets say Im given a random character array such as: 'aaabee' and i want to find the longest sequence of vowels. How would i go about doing this?
so far I have:
cArr = 'aaabee';
vow = ['a', 'e', 'i', 'o', 'u'];
ans = strfind(cArr, vow);
but this just returns: [ ]
anyhelp would be appreciated!
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Answers (2)
Ameer Hamza
on 16 Nov 2020
Edited: Ameer Hamza
on 16 Nov 2020
You can use regexp
cArr = 'xzyhd';
vow = '([aeiou]+)';
tkns = regexp(cArr, vow, 'tokens');
if isempty(tkns)
n = 0;
else
n = max(cellfun(@numel, [tkns{:}]));
end
Result
>> n
n =
5
3 Comments
Setsuna Yuuki.
on 16 Nov 2020
Edited: Setsuna Yuuki.
on 16 Nov 2020
cArr = 'aaabee';
vow = ['a', 'e', 'i', 'o', 'u'];
for n=1:length(vow)
a = strfind(cArr, vow(n)); %search letter by letter
repeat{n} = a; %place in "cArr"
if (a ~= NaN)
long(n) = length(a); %number of repetitions
else
long(n) = 0;
end
end
t = table(vow',long')
Table:
4 Comments
Setsuna Yuuki.
on 16 Nov 2020
Edited: Setsuna Yuuki.
on 16 Nov 2020
has been interesting this problem, i changed all code because I understood bad your problem.
clear large;
cArr = 'aaeeaaapriioaeaaa';
vow = ['a', 'e', 'i', 'o', 'u'];
var = 1;
for n=1:length(vow)
a = strfind(cArr, vow(n));
if(var == 1)
var(length(var):(length(var)+length(a))-1)=a;
else
var(length(var)+1:length(var)+length(a))=a;
end
end
var = sort(var); m = 0;
cont = 1;
for n = 1:length(var)-1
if(var(n) == (var(n+1)-1) && n ~= length(var)-1)
cont = cont +1;
elseif (var(n) ~= (var(n+1)-1))
m = m+1;
large(m) = cont;
cont = 1;
elseif(n == (length(var)-1))
cont = cont+1;
m = m+1;
large(m) = cont;
end
end
[longSeq, index] = max(large);
fprintf("The longest sequence is %i and is the sequence %i \n",longSeq, index);
I think I did this in C ++ jaja xd
Image Analyst
on 16 Nov 2020
What's the use case for this quirky thing? Why do you need to do it? It's not your homework you're asking people to do for you, is it? What's the real world use for this?
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