how to solve iterative equations ?

Hi,

Please guys help me out. I have a problem in solving the iterative equation. i have an equation say 2u-3+ln(u-0.5)+2x=0. For every iteration, say upto 30 iterations, 'x' changes as 0:dx:1, hence for every change of x, i need to find 'u' and store it. I have tried using fzero,inline,solve but could not get the vector 'u'. Can anyone please help me out in writing this code

[Matt J]

FZERO should have worked. You should show your coding attempt so we can see what might have gone wrong.

Answer 1

[Youssef Khmou]

hi, you can solve your equation by many ways , try :

 a=solve('2*u-3*log(u-0.5)+2*x','u')
 u=subs(a,linspace(0,1,30));
 plot(u) % this is the solution

Now you can verify your solution U :

 X=linspace(0,1,30);
 ZZ=2*u-3*log(u-0.5)+2*X;

[José-Luis]

Please don't post answers to what seem to be homework questions.