How do we take the inverse fourier transformof this image

I need to find the inverse tramsform of the second image

Answer 1

[Bastian Arturo Romero Mardones]

Your image:

img = imread('imagen','jpg');
h = ifft2(img); %inverse fourier transform
imagesc(abs(h(:,:,1)));

inverse fourier transform:

[r,c,~] = size(h);
H = abs(h(fix(c/2):end,fix(c/2):end,1));
H2 =[H fliplr(H)];
H = [H fliplr(H); flip(H2)];
figure
imagesc(H)

[Arya Gopan]

Sir this is the code I used so far from reading the image to taking its fourier transformand then cropping one part of it. Can you please check the last part of the code. I want the inverse fourirer transform using ifftshift

clear all

I = imread('a35.jpg');
I = rgb2gray(I);
[r , c] = size(I);
for i = 1:r
    X(i,:)=fft(I(i,:));
end
for j = 1:c
    Y(:,j)=fft(X(:,j));
end
figure(1)
imshow(I)
figure(2)
M=Y;
M=fftshift(M);
Ab=abs(M);
Ab=(Ab-min(min(Ab)))./(max(max(Ab))).*225;
imshow(Ab)



X=zeros(size(Ab));
X(475:563,556:639,:)=1;
p = Ab.*X;

subplot(2,1,1)
imshow(Ab);
title('Orginal')

subplot(2,1,2)
imshow(p);
title('Cropped')

IFF=(ifftshift(ifft(p)));
Final=uint8(real(IFF));
figure
imshow(Final);