Random square sampling for single channel images

For a single-channel image with random square sampling, Not a fixed sub-window,how to generate random squares usingMATLAB, an example is as follows,Thank you

Answers (2)

Hi, here is one working example.
Hope this helps!
% Read the original image
img = imread('cameraman.tif');
[row, col, ~] = size(img);
imgSize = [row, col];
% Specify dimension of the random square
squareSize = [50, 50];
% Calculate crop rectangle
maximumPosValue = (imgSize - squareSize + 1);
initialRandomPos = [randi(maximumPosValue(1)), randi(maximumPosValue(2))];
cropRect = [initialRandomPos(2), initialRandomPos(1), squareSize(2)-1, squareSize(1)-1];
% Crop the image
imgCropped = imcrop(img, cropRect);
% Visualize results
out = imtile({img, imgCropped}, 'BackgroundColor', 'w');
figure
imshow(out)
title('Original image | Random cropped image');

2 Comments

Very good, but your square sampling is a set fixed window size, what I want is to generate a square area based on the coordinates of the image formed by random numbers,the sampled square area appears randomly in the image and square size is variable,such as image(x1:x2, y1:y2)
@len Bruce you can randomize the sqare window size like below.
% Read the original image
img = imread('peppers.png');
[row, col, ~] = size(img);
imgSize = [row, col];
% Specify dimension of the random square
val = randi(min(imgSize));
squareSize = [val, val];
% Calculate crop rectangle
maximumPosValue = (imgSize - squareSize + 1);
initialRandomPos = [randi(maximumPosValue(1)), randi(maximumPosValue(2))];
cropRect = [initialRandomPos(2), initialRandomPos(1), squareSize(2)-1, squareSize(1)-1];
% Crop the image
imgCropped = imcrop(img, cropRect);
% Visualize results
out = imtile({img, imgCropped}, 'BackgroundColor', 'w');
figure
imshow(out)
title('Original image | Random cropped image');

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Generate the coordinates of the image square sampling based on random numbers,such as the upper left and the lower right co-ordinates of the ith random sub-window is denoted by (x1,y1)and (x2,y2)respectively. (image(x1:x2, y1:y2))

Asked:

on 28 Dec 2020

Answered:

on 28 Dec 2020

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