How does the code work?

1 view (last 30 days)
Faris Sulam
Faris Sulam on 9 Jan 2021
Commented: Faris Sulam on 9 Jan 2021
Hi guys, I am learning on how to use MATLAB and currently im learning about making a user defined function for the Simpson's rule. The following is the code that I am looking at from the textbook "Numerical Methods for Engineers and Scientists":
function [ s ] = test( FunName,a,b)
N=2;
h=(b-a)/N;
x=a:h:b;
y=FunName(x);
MaxTol=1.0;
I1=h/3*(y(1)+4*sum(y(2:2:N))+2*sum(y(3:2:(N-1)))+y(N+1));
N=2*N;
check=0;
while check==0;
h=(b-a)/N;
x=a:h:b;
y=FunName(x);
I2=h/3*(y(1)+4*sum(y(2:2:N))+2*sum(y(3:2:(N-1)))+y(N+1));
CurTol=abs(I1-I2)/I1*100;
if CurTol>MaxTol
check=0;
N=N*2;
I1=I2;
elseif CurTol<=MaxTol
check=1;
I1=I2;
end
end
disp(I1)
end
Now i just want to ask on what 'check' does in this code? Presumably that 'check' here tells MATLAB to continually iterate but I dont understand how it stops it. Thanks in advance
  4 Comments

Sign in to comment.

Answers (0)

Categories

Find more on Programming in Help Center and File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!