How to use min function so that it stops at the first minimum value in a column matrix, stores values, and then continues going until it finishes the entire matrix? (details below)
3 views (last 30 days)
Show older comments
would like to write a loop where i would like to sort through a column vector and stop when it hits a min value, these values would get stored in a subsequent array, then it keeps going until it hits another min value, and then these values would get stored in a subsequent array, and so on until it reaches and finishes the entire column vector. How would I go about doing this?
4 Comments
Rik
on 9 Jan 2021
Is that minimum value guaranteed to be the same value? Or should the function determine a new minimum value?
Answers (2)
Rik
on 9 Jan 2021
Edited: Rik
on 9 Jan 2021
If the minimum value you're after is the same throughout the array:
data=[0.200 0.300 0.400 0.001 0.002 0.003 0.004 0.003 0.002 0.001];
ind=find(ismember(data,min(data)));
ind=[0 ind];
ind_start=ind(1:(end-1))+1;
ind_end= ind(2: end ) ;
output=arrayfun(@(i1,i2) data(i1:i2),ind_start,ind_end,'UniformOutput',false);
celldisp(output)
Alternatively, if the minimum can change over the array:
output={};ind1=0;
data=[0.200 0.300 0.400 0.0001 0.002 0.003 0.004 0.003 0.002 0.001];
% ^ added a 0
while ind1<numel(data)
ind1=ind1+1;
[~,ind2]=min(data(ind1:end));
ind2=ind1+ind2-1;
output{end+1}=data(ind1:ind2); %#ok<SAGROW>
ind1=ind2;
end
celldisp(output)
0 Comments
Bruno Luong
on 9 Jan 2021
Edited: Bruno Luong
on 9 Jan 2021
A=[0.200 0.300 0.400 0.001 0.002 0.003 0.004 0.003 0.002 0.001]
imin=find(A==min(A));
lgt=diff(union(imin,[0 length(A)]))
C=mat2cell(A,1,lgt);
Check (the min values are located at the end)
>> C{:}
ans =
0.2000 0.3000 0.4000 0.0010
ans =
0.0020 0.0030 0.0040 0.0030 0.0020 0.0010
0 Comments
See Also
Categories
Find more on Line Plots in Help Center and File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!