How can I apply circular shift on bits in MATLAB?
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Sana Shaikh
on 11 Apr 2013
Commented: sushmitha kemisetti
on 6 Jun 2017
I want to apply shift right operation on aset of bits
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Accepted Answer
Youssef Khmou
on 12 Apr 2013
hi,
suppose you have a vector a=011000011, then shift circularly the vector :
b=circshift(a,[1 1]), % if 1 is >0 then the vector is shifted the right
b=circshift(a,[1 -1])
b=circshift(a,[1 2]),
...
More Answers (1)
Walter Roberson
on 11 Apr 2013
MATLAB does not offer that operation directly.
You can extract the bits that would be shifted "off the bottom", do the shift, and then put the bits back on top. Or you can proceed numerically, such as
mod(x,2)*2^7 + floor(x/2)
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Walter Roberson
on 6 Jun 2017
Do you want the individual bits to be left shifted, or do you want the elements to be left shifted relative to the other elements? For example if you had A = uint8([1 2 3 129]) to be circular left shifted by 2, then do you want the result B = uint8([3 129 1 2]) or do you want the result B = uint8([4, 8, 12, 6]) ?
If you want the elements to be left shifted relative to each other, then
B = circshift(A, -K, 2);
If you want the bits to be circular shifted, then use the code I posted above (which I made a couple of corrections to a moment ago.)
If you want the bits to be circular shifted and you want the operation to be expressed mathematically, it is possible. In the above code, replace
shifted_uMatrix = bitshift(uMatrix, K, uc) + bitshift( uMatrix, K-wl, uc);
with
shifted_uMatrix = mod(uMatrix, 2^(wl-K)) * 2^K + uMatrix ./ 2^(wl-K);
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