How can I use uigetfile to get the file path?

Hello, I was wondering if I could use the function uigetfile to get the complete file path string.

Answer 1

[Image Analyst]

The documentation for uigetfile() is remiss in not showing any examples that use fullfile() to construct the full file name of the chosen file. Here is how you do it:

[baseName, folder] = uigetfile();
fullFileName = fullfile(folder, baseName)

[Alejandro]

Thank you! I was looking for the full file path and this is it!

Answer 2

[Matt J]

The 2nd output argument of uigetfile() gives the path info. See

 >>doc uigetfile

[Jan]

Exactly. Reading the help and doc text is a good strategy, when you have questions conderning a command.