'fix' function misbehaving

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Charlie Bright
Charlie Bright on 21 Jan 2021
Commented: Star Strider on 21 Jan 2021
Hi everyone,
I have a table of data.
The first column of the table reads how many heartbeats there have been. It's a number that increases with each row by 1. So I have 9 beats, hence 9 rows, reading 1 through 9.
Outside the table, I have a variable 'Z' calculated from two other variables 'X' and 'Y' which I previously specify.
X and Y are variables from some simulations I have been doing. X is dependant on the value of Y, but Y is held as a constant so that shouldn't matter.
X = 38.2
Y= 25
Z=X*Y, so Z=955.000. Simple enough.
Now, sometimes Z is not a whole number.
For example, one of my simulations had X=19.1000 and Y=25, giving a value of Z = 477.5000
For the next column of my table I want to multiply the heart-beat number by the integer part of Z.
Using the 'fix' function, Z=fix(Z), works perfecly when Z=477.5000. Z returns 477.
However when Z=955.0000, fix(Z) returns 954.
When I type out "Z=955.0000" in place of getting Z from the previous calculation then fix(Z) returns 955.
The same issue is ocuring with the floor funcition, however the round function returns 955.
Any idea what's going wrong? Thanks

Accepted Answer

Star Strider
Star Strider on 21 Jan 2021
Temporarily set the format to long, and then also do:
dZ = Z - 955
and check the result. This is most likely the result of rounding in the display, and floating-point approximation error. See Floating-Point Numbers for an extended discussion.
  2 Comments
Charlie Bright
Charlie Bright on 21 Jan 2021
Hi Star,
Thanks for getting back to me.
The long format helped me see that the X value of 38.2 was actually 38.1999 and therefore Z's true value is 954.9999 hence the rounding.
I'll have to have a think about how that changes my calculations and have a play with the code.
Thanks again!
Star Strider
Star Strider on 21 Jan 2021
My pleasure!
If my Answer helped you solve your problem, please Accept it!
.

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