Applying an integer to a specific cell of a matrix

I need to apply a single integer across a group of cells in a matrix. I honestly have no idea how to do this. Here's the code that im working with right now

x = [0:0.1:3];
y = [-2:0.13:2];
Load = 0; 
for (x = 1:31)
    for (y = 1:31)
        Load(x,0) = 10;
    end
end

But that and several other variations i've tried are not working whatsover.

The Integer "Load" needs to be inserted into all values of x where y = 0.

How can I do this?

[David Hill]

Not sure what you want. With y=-2:.13:2, there are no y==0 in the array. What matrix are you trying to form.

[John D'Errico]

You don't need parens in a for loop. That is, this is not standard syntax (though it seems to work)

for (x = 1:31)

instead, write it as:

for x = 1:31

[DEEPAK Chekuri]

In this case 'y' will never be zero.

however if you have ,another list of y(which has zeros) ,then try this

for i=1:31
    if y[i]==0
        x[i]=Load;
    end
end

[Stephen Cobeldick]

@DEEPAK Chekuri: that is not valid MATLAB code. You seem to be mixing up languages.

Answer 1

[Pratyush Roy]

Hi Noah,

The following code might be helpful :

x = 0:0.1:3;
y = -2:0.13:2;
Load = 10;%Integer that we want the elements to replace with  
for i = 1:31
        if y(i)==0;
            x(i)=Load;
        end
end

Hope this helps!

Regards,

Pratyush.

[Walter Roberson]

x(y==0)=Load;

No loop needed

[Stephen Cobeldick]

"The following code might be helpful "

Even more helpful would be to read this comment from one week ago:

https://www.mathworks.com/matlabcentral/answers/734427-applying-an-integer-to-a-specific-cell-of-a-matrix#comment_1303542