Initialize field values in a structure + create a list of zeros(10,10)

Hi everyone, I want to initialize the same field for several indexes in a structure by some zeros(10,10), and I can't figure out how.

Already took me a while to figure out how to just initialize them to 0:

[test(5:9).field] = deal(0,0,0,0)

Which works but

• I don't want to initialize by a scalar zero but by a 10x10 zeros matrixes
• And obviously I don't want to repeat the

zeros(10,10)

as many times as I have indexes to initialize.

All the options I find are some kind of concatenation functions (for example repmat) which will obviously won't do the job.

There must be an easy an elegant way, but I can't seem to find it :/

Thanks in advance!

P.S.: and obviously, I'm not looking for a loop.

Answer 1

[The Gogo]

CORRECTION: actually the correct answer is in the comments of this answer. by Stephen Cobeldick.

Ok, sorry I finally found the answer thanks to: https://www.mathworks.com/matlabcentral/answers/106681-initializing-a-struct-with-n-d-fields#answer_115699

test2 = cell(4,1);
test2(:) = zeros(10,10);
[test(5:9).field] = deal(test2);

Sorry for disturbing. I hope my struggle might be useful to some other people. If anyone has a shorter way, I'm still interested.

[darova]

Thanks for your answer. YOu can accept it so other people can use it

[Stephen23]

Simpler without the cell array:

mat = zeros(10,10);
[test(5:9).field] = deal(mat)

test = 1x9 struct array with fields:
    field

test(4).field

ans =

     []

test(5).field

ans = 10×10

0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0

[The Gogo]

Cool, thx! Actually this is the only right answer, mine does something else.