Index exceeds the number of array elements (1).

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marie lasz
marie lasz on 18 Feb 2021
Edited: marie lasz on 20 Feb 2021
Hello ,
Can someone tell me where am I wrong here? I am retrieving only 1024 values from 3072 after comparing each row from 3 same columns.
w = zeros(1, 1024);;%1024 length
l=length(h_im);
x=4;
y=2;
for k = 1 : numel(h_im)
a =zeros(1, 4096);
end
for i = 1 : numel(d)
dl = zeros(1, numel(W)); length %1024
for h =1:3
if a(i*3+h)>0 %%%% error is here
dl = dl+1;
else
dl = dl-1;
end
end
end
  3 Comments
marie lasz
marie lasz on 18 Feb 2021
Yes I know but I need only 1024 values , i have 3 columns anfd 1024 rows = 3072 values now i want to compare each row and extract one value .
marie lasz
marie lasz on 18 Feb 2021
even by making length equal in each loop still gives this error

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Answers (1)

Image Analyst
Image Analyst on 18 Feb 2021
for k = 1 : numel(h_im) % the length is 3072
a(k) = w_im{k}(x,y) - h_im{k}(x,y);
end
and
if dl > 0
w(i) = 1;
else
w(i) = 0;
end
simplifies to
w(i) = double(dl > 0); % Double is not necessary if you're happy with w as a logical.
  5 Comments
marie lasz
marie lasz on 19 Feb 2021
I solved the problem. thank you for your time :-)
Rik
Rik on 19 Feb 2021
Next time, please try to post a minimal working example. That means you post as much code as is needed to result in the unwanted behavior, but not more.
You should also do yourself a favor: write comments. I tend to suggest that half of your m file should be green. That is probably too much, but if you really try to explain the purpose of every line, you will make it a lot easier for others to read your code. In two weeks you will be unable to understand what you did here.

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