Asked by john borsellino
on 9 May 2013

c=19;

>> D=[];

>> for k=1:c;

Z=[X(:,1),Y(:,1)];

p=anova1(Z)

D=save(p)

X(:,1)=[];Y(:,1)=[];

end

Answer by James Kristoff
on 13 May 2013

Accepted Answer

% X and Y are 3x19 matricies

%

% This syntax makes sure that if you end up having more (or less) columns

% in the future, you don't need to change the code

numColumns = size(X, 2);

% Pre-allocate for speed (create a 1 x numColumns vector)

p = zeros(1, numColumns);

% I used length(p) here to signal the intent that the loop is meant for

% modifying the vector p

for k = 1:length(p);

% using the loop variable *k* means that MATLAB will use a different

% column from X and Y to create Z for each loop

Z=[X(:,k),Y(:,k)];

% this will store the resulting value in the k-th position in the vector

% *p*

p(k)=anova1(Z);

end

john borsellino
on 14 May 2013

john borsellino
on 16 May 2013

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Answer by bym
on 9 May 2013

c=19;

% D=[];

p = zeros(c,1); % preallocate

for k=1:c;

Z=[X(:,1),Y(:,1)];

p(k)=anova1(Z);

%D=save(p) unecessary

%X(:,1)=[];Y(:,1)=[]; don't change X or Y!

end

john borsellino
on 10 May 2013

john borsellino
on 10 May 2013

...and thanks for your input and time...only 8 weeks on matlab...be gentle

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## James Kristoff (view profile)

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## john borsellino (view profile)

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## john borsellino (view profile)

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