How can I know if the repeated numbers of array A appear in B , and if so count their repetition (for A and B ) and divide their countings? A and B have different dimensions.

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I have two files, and I want to count for both files how many times the values are repeated in a certain column. And if the repeated values appear in both files (for instance: value 0.5 appears repeated in file A and also in file B) I want their counting to be divided.
Example: in file A, column 1 I have 230 number "2" , 430 number "3"....etc
in file B, column 1 I have 500 number "2" , 620 number "3"....etc
After that I need to divide 230 by 430.
500 by 620....and so on.
That's what I did so far:
A = load('fileA.csv');
B = load('fileB.csv');
a = A(:,1);
b = B(:,1);
[count_a,mag_a]=hist(a,unique(a))
[count_b,mag_b]=hist(b,unique(b))
So, in mag_a I have a list of numbers, and in count_a how many times these numbers appear repeated. Same for mag_b and count_b.
I don't know how to tell the program something like: If number "x" is repeated in A and also in B, count and divide the counting.
Thank you!

Accepted Answer

Athul Prakash
Athul Prakash on 15 Mar 2021
Hi Ana,
You may extract the common elements of the array using intersect() function.
common = intersect(mag_a, mag_b);
Then you may create an array of common counts:
countCommon_A = zeros(length(common),1);
countCommon_B = zeros(length(common),1);
for i=1:length(common)
idx = find(mag_a == common(i));
countCommon_A = count_a(idx);
countCommon_B = count_b(idx);
end
From here, you may divide the counts as needed.
Hope it helps!
  3 Comments
Athul Prakash
Athul Prakash on 15 Mar 2021
Yes that's right. I left out the division in my answer since I wasn't sure what you were trying to divide, but this sounds right.

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