Puzzling syntax: 2:4:6:8:10:12

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Jan
Jan on 28 May 2013
Dear Matlab-profis and beginners,
What do you expect as result of this:
a = 2:3:4:5:6:7
And this:
b = 2:3:4:5:6:7:8
What reasons do you have for your assumptions?
Letting Matlab find the results is too easy. But even if you do, do you have good arguments for the results? Btw, The results are equal for 6.5, 2009a and 2011b.

Accepted Answer

Daniel Shub
Daniel Shub on 29 May 2013
The documentation lists the colon operator as having the 6th highest precedence and says that
Within each precedence level, operators have equal precedence and are evaluated from left to right
What is not clear from the precedence documentation is if a:b:c has one or two colon operators. The documentation for the colon operator says
To generate a series that does not use the default of incrementing by 1, specify an additional value with the colon operator (first:step:last).
which suggests to me that a:b:c is a single colon operation (I think this is probably the weakest aspect of the documentation).
The documentation of the colon function says
COLON(J,K) is the same as J:K and COLON(J,D,K) is the same as J:D:K.
I interpret "the same" to me that the converse is also true and that J:K is the same as colon(J,K) and J:D:K is the same as colon(J,D,K).
Based on this I would assume a left to right substitution of triplets.
a = 2:3:4:5:6:7
= colon(2,3,4):5:6:7
= 2:5:6:7
= colon(2,5,6):7
= 2:7
= colon(2,7)
= [2,3,4,5,6,7]
b = 2:3:4:5:6:7:8
= colon(2,3,4):5:6:7:8
= 2:5:6:7:8
= colon(2,5,6):7:8
= 2:7:8
= colon(2,7,8)
= 2
For the additional case given in the comment to IA's answer of 2:3:6:7 we need a little more of the documentation
If you specify nonscalar arrays, MATLAB interprets j:i:k as j(1):i(1):k(1).
a = 2:3:6:7
= colon(2,3,6):7
= [2, 5]:7
= colon(2, 7)
= [2,3,4,5,6,7]
  3 Comments
Jan
Jan on 1 Jun 2013
Now I've struggled for 2 hours with Matlab's documentation and Google to find a documentation about valid numerical notations. My trials to search ended all at descriptions of s/f/printf() and format(). All I could found was a printed documentation of Sinclair ZX-81 Basic interpreter. This demonstrates a weakness of my search methods.
I'm going to ask the technical support.

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More Answers (1)

the cyclist
the cyclist on 29 May 2013
I would expect MATLAB to interpret this left-to-right, grouping in the form
M:I:N
where possible, so
a = 2:3:4:5:6:7
= (2:3:4):5:6:7
= 2:5:6:7
= (2:5:6):7
= 2:7
= [2 3 4 5 6 7]
and
b = 2:3:4:5:6:7:8
= (2:3:4):5:6:7:8
= 2:5:6:7:8
= (2:5:6):7:8
= 2:7:8
= 2
This is what I get in R2013a.
  3 Comments
Jan
Jan on 29 May 2013
Edited: Jan on 29 May 2013
Thank you, Cyclist. I found an equivalent piece of code in the question of a beginner, who assumed 2:3:4:5:6:7 to be the correct method to create 2:7. It seemed to be a prove for the correctness, that the expected result is produced. But the different result of 2:3:4:5:6:7:8 looked strange for the user, and for me even both have the same level of strangeness.

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