sprintf conflict in operations
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    Opariuc Andrei
 on 24 Mar 2021
  
    
    
    
    
    Commented: Star Strider
      
      
 on 24 Mar 2021
            receiving 5 values for Mt2b while using sprintf for Pmax (i used to to get an exact  value without variables) .if i remove sprintf from Pmax i'm receiving 1 value as needed .The question being how can fix my result for Mt2b without having to remove sprintf from Pmax ?
Fa=88050;
E=2.1*10^5;
R=200;
r0=1.11*((Fa*R)/E)^(1/3)
Pmax=sprintf('%.0f\n',0.39*((Fa*E^2)/R^2)^(1/3))
Mt2b=sprintf('%.0f\n',((pi^2)/8)*0.2*Pmax*r0^3)
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Accepted Answer
  Star Strider
      
      
 on 24 Mar 2021
        To use ‘Pmax’ in a calculation, it has to be turned back into a number.  
Try this: 
Mt2b=sprintf('%.0f\n',((pi^2)/8)*0.2*str2double(Pmax)*r0^3)
producing: 
Mt2b =
    '50709
     '
.
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