Why fopen does not accept the path when it is assigned to a variable.
1 view (last 30 days)
Show older comments
filename=['tests/testbkc/result-1/abc.txt']; fid=fopen('filename','w')
Here fid returns bigger than 3 but it does not create any file.
If I wrote the path directly into fopen then everything is okey. But I need to use variable.
what should be the type of filename? Isnt it char?
Does anybody have an idea? Thanks
0 Comments
Accepted Answer
Ahmed
on 7 Jun 2013
omit the the '' to get the content of the variable filename.
fid=fopen(filename,'w')
0 Comments
More Answers (0)
See Also
Categories
Find more on Startup and Shutdown in Help Center and File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!