Unable to perform assignment because the size of the left side is 1-by-1 and the size of the right side is 1-by-2.
1 view (last 30 days)
Show older comments
I get the error "Unable to perform assignment because the size of the left side is 1-by-1 and the size of the right side is 1-by-2." when I run the script. I am not sure where I am going wrong.
function script:
function [w1i, w2i, ti] = Basic_Euler(h ,m1 ,m2 , k1, k2, k3, c1, c2, c3, z1, z2,N,t0, x1,x2, tf)
neqn1 = length (x1);
neqn2 = length (x2);
ti = linspace ( t0, tf, N+1 );
w1i = [zeros( neqn1, N+1 ) ];
w2i = [zeros( neqn2, N+1 ) ];
for i = 1:N
z1(i+1) = z1(i) + h.*(((c2.*z2(i))-((c1+c2).*z1(i))+(k2.*x2(i))-((x1(i).*(k1+k2))))./m1);
x1(i+1) = x1(i) + h.*(z1(i));
z2(i+1) = z2(i) + h.*(((c2.*z1(i))-((c2+c3).*z2(i))+(k2.*x1(i))-((k2+k3).*x2(i)))./m2);
x2(i+1) = x2(i) +h.*(z2(i));
w1i(1:neqn1,i+1) = x1;
w2i(1:neqn2,i+1) = x2;
end
end
Master Script:
function Ass2()
close all
t0 = 0;
tf = 100;
h = 0.1;
N = (tf - t0)./h;
k1 = 3;
k2 = 2;
k3 = 1;
c3 = 0.01;
m2 = 4;
c1 = 0.03;
c2 = 0.02;
m1 = 1;
x1 = -1;
x2 = 6;
z1 = -1;
z2 = 3;
[x1,x2, ti] = Basic_Euler(h ,m1 ,m2 , k1, k2, k3, c1, c2, c3, z1, z2,N,t0, x1,x2, tf);
figure1 = figure;
axes1 = axes('Parent',figure1,'FontSize',20,'FontName','Times New Roman');
box(axes1,'on');
grid(axes1,'on');
hold(axes1,'all');
xlabel('t','FontSize',20,'FontName','Times New Roman');
ylabel('x','FontSize',20,'FontName','Times New Roman');
plot1 = plot(ti,x1,'Parent',axes1,'LineWidth',3);
set(plot1(1),'Marker','diamond','DisplayName','Basic Euler 1');
legend(axes1,'show');
figure2 = figure;
axes1 = axes('Parent',figure2,'FontSize',20,'FontName','Times New Roman');
box(axes1,'on');
grid(axes1,'on');
hold(axes1,'all');
xlabel('t','FontSize',20,'FontName','Times New Roman');
ylabel('x','FontSize',20,'FontName','Times New Roman');
plot1 = plot(ti,x2,'Parent',axes1,'LineWidth',3);
set(plot1(1),'Marker','diamond','DisplayName','Basic Euler 1');
legend(axes1,'show')
0 Comments
Answers (1)
Pavan Guntha
on 29 Mar 2021
Hi Shaan,
The error is due to the line 15 of the function Basic_Euler:
w1i(1:neqn1,i+1) = x1;
The size of x1 is getting changed within the function due to the line:
x1(i+1) = x1(i) + h.*(z1(i));
Because of this reason, the size mismatch is happening. The possible solution might be to change the line 15 & 16 in the function as follows:
w1i(1:neqn1,i+1) = x1(i+1);
w2i(1:neqn2,i+1) = x2(i+1);
Hope this helps!
See Also
Categories
Find more on Numerical Integration and Differential Equations in Help Center and File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!