numerical problem of quadprog

Hi, I am trying to solve a badly scaled quadprog problem
H = [5e15, -1.66e15, 1.02e9, -1.23e10;
-1.66e15, 1.11e15, 1.42e6, 8.3e9;
1.02e9, 1.42e6, 2.5e6, 93;
-1.23e10, 8.32e9 , 93, 5e5 ]
f = [-4.76e7, 3.49e7, -2.19, 2.31e3]'
Aieq = [1/2, -1/3, 0, 0]
bieq = 0
when I try to use quadprog(H,-f,Aieq,bieq), MATLAB indicates problem successfully solved, but if you check inequality constraint manually, Aieq * x = a very very small positive number.
What is the best way to solve this numerical problem?
  1. set 'ConstraintTolerance' to a small number?
  2. set bieq = a very small negative number?
  3. rescale matrix H and f?

5 Comments

I think this must be the priority:
  • rescale matrix H and f?
thank you for your replying. Is there a general formula to re-scale my problem? How to determine the rescale factor? Because I need to run thousands of similar problems, all of them can give "optimal solution found" message, but some of them violate the inequality constraint, some of them don't.
There is MATLAB function normalize to help you to do such thing.
It is on recent version only though.
Roughly the "ideal" method is to change the decision variable to y, where
sqrtm(H)*y = x
so that the Hessian becomes identity with respect to y.
A quick and dirty rescaling is then
sqrt(diag(H)).*y = x
Thanks a lot for your replying, can I let
scal = sqrt(vecnorm(H))
and do
H_adj = H./(scal.'*scal); f_adj = f./scal.'
and
quadprog(H_adj,-f_adj,Aieq,bieq)?
You have also to modify Aieq.

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R2020b

Asked:

on 13 Apr 2021

Commented:

on 13 Apr 2021

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