Force super class to not call overloaded methods of the subclass
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I have a base class and subclass inheriting from it. Base class has method A. Subclass overloads that method. I want to force the base class to use (only in some places) it's own method, not the one overloaded by subclass. Is there any way to do it?
Thank you
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Answers (3)
Matt J
on 28 Apr 2024
Edited: Matt J
on 28 Apr 2024
In any superclass method, you can test whether the invoking object is of the base class or one of its children. Depending on the result of this test, you can clone the child's base component for the purposes of calling base methods only. The attachments give an example of this.
parent=myclass(1), child=mysubclass(1,2)
parent.callingMethod()
child.callingMethod()
child.callingMethod(scope="Parent")
1 Comment
Matt J
on 28 Apr 2024
Edited: Matt J
on 28 Apr 2024
You can also have the desired calling scope set through the a property, as in the attached modifications. This would be the better design if you want all methods to make this sort of scope check.
parent=myclass(1), child=mysubclass(1,2)
parent.callingMethod()
child.callingMethod()
child.callingScope="Parent";
child.callingMethod()
Shraddha Jain
on 22 Jun 2021
Hi Naum,
When you create an object obj of a superclass and then use obj to call the overloaded (or any) method of the superclass, the method defined in the superclass is called and not the one of the subclass.
2 Comments
Steven Lord
on 26 Apr 2024
You can call a superclass method even if the subclass overloads or overrides that method only from within that method itself. So if the superclass and subclass both define a method foo(), inside the subclass foo() method you can call the superclass's foo() method.
You can also have the subclass's constructor call the superclass's constructor (even though they don't have the same name.)
3 Comments
Steven Lord
on 26 Apr 2024
I'm not sure I understand what you're trying to do. Can you describe in a little more detail what problem you're trying to solve (not how you're hoping to implement it; describe the why not the how), or perhaps what design pattern you're trying to implement? With that information we may be able to suggest an approach to achieve your goal (or explain if it smells a bit funny to us.)
A.B.
on 28 Apr 2024
Edited: A.B.
on 28 Apr 2024
The superclass has method make and premake. The subclass also overloads both methods. It appears any method within the superclass which is calling make or premake, calls the overloaded methods of the subclass (and not those of superclass). This behavior messes up everything. I sincerely hope I am doing something wrong, otherwise this behavior is completely counter intuitivie for me.
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