How can I solve this ?

1. Create a function “secant method” that returns a variable “results”. These should later contain a vector of results from the iterations.

2. The method should transfer an x_0, x_1 value, the function and the number of iterations to get.

3. Initialize the vector with ones in the dimension 1 x (number of iterations +2).

4. Assign the x_0 and x_1 values to the first two digits of the vector.

5. Iterate over the result vector in a loop.

6. Now calculate the x_n value in each loop pass according to the Secant formula: x_n + 1 = x_n - (x_n - x_n_1) / (f (x_n) - f (x_n-1)) * f (x_n)

7.After the calculation, reassign the variables for the next run (keyword: x_n-1, x_n).

8. Add the current result to the result vector.

9. Call the newly created function with an anonymous function f = x ^ 2-2, 4 iterations and the starting values 1 and 2 (see lecture, exercise) and check the results.

10. Make sure that no errors or unnecessary output are displayed.

[David Hill]

What have you done? Show us your code and ask a specific question.

[Mohammad Al Kotob]

Hello , thats what i've done :

function [result]= secant method (x_0,x_1,f,k)

result = ones(1,(k+2));

result(1)= x_0; result(2)= x_1;

x_n=x_0;

x_n_1=x_1;

for k=1: length(result)

x_n1=x_n-(x_n-x_n_1)/(f(x_n)-f(x_n_1))*f(x_n);

x_n_1=x_n;

x_n=x_n1;

result(k)=x_n;

end

end

Answer 1

[Nagasai Bharat]

Hi,

Initially the function would show an error due to it's name(no space to be present between words). Correct way would be to use "secant_method".

The following documention would help you understaning the correct format while using function.

Declare function name, inputs, and outputs - MATLAB function (mathworks.com)

[Mohammad Al Kotob]

Thanks !