Random sample, I want the 5% of the data per each hour
2 views (last 30 days)
Show older comments
Rachele Franceschini
on 4 Jun 2021
Edited: Scott MacKenzie
on 4 Jun 2021
I have a database with 19 columns. One column has date, month, year and hour. I would like to get, per each hour, the 5% of the data. Naturaly, I would like to see all the other data, along with the column of time.
Can you help me?
I saw the comand resample, but at the moment, I am in difficulty.
2 Comments
Scott MacKenzie
on 4 Jun 2021
It would help if you post the data -- or, better yet, a subset of the data -- and any code you have written so far.
Accepted Answer
Scott MacKenzie
on 4 Jun 2021
Edited: Scott MacKenzie
on 4 Jun 2021
There might be a way to simplify this, but I believe the script below achieves what you are after...
% read all the data into a table
T = readtable('https://www.mathworks.com/matlabcentral/answers/uploaded_files/642145/Cartel1.xlsx');
% build a vector of 0s and 1s --> each 1 occurs where the hour changes
dt = datetime(T{:,3});
hr = hour(dt);
z = diff(hr);
% build a vector of the indices where the time changes
idx = find(z); % indices of 1s in z
idx = [0; idx];
% build a vector of new indices, selecting at random 5% of the rows for each hour
idxNew = [];
for i=2:length(idx)
n = round(0.05 * (idx(i) - idx(i-1)+1));
idxNew = [idxNew, randi([idx(i-1)+1, idx(i)], 1, n)];
end
% create new table with 5% of the rows for each hour
Tnew = T(idxNew,:);
With this script, your data set is now much smaller. See below. That's the general idea, right?
2 Comments
Scott MacKenzie
on 4 Jun 2021
@Rachele Franceschini You're welcome.
BTW, I just fixed a small bug in the answer script. The second index in each range included the first row of the following hour. It's fixed now. Good luck.
More Answers (1)
KSSV
on 4 Jun 2021
Let A be your data matrix.
[m,n] =size(A) ;
p = round(5/100*m) ;
idx = randsample(m,n) ;
iwant = A(idx,:)
0 Comments
See Also
Categories
Find more on Startup and Shutdown in Help Center and File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!