is there a way to make it to where if a checkbox is checked then that corresponding word will show up in the text area?

i am using app designer and i am trying to get it to where if a check box is checked then it will display the name in the text area. this below is what in have for when a button is pushed fpmc fpcoy and fprg are set as words in the properties. and i want it to show up if the box for those is checked shown in the picture

and i want it to display like this

Flatpack mc

Flatpack Coy

Flatpack Rg

not Flatpack mc Flatpack Coy Flatpack Rg

i can get it to work but only for the Rg one

thank you

function DoneButton_4Pushed(app, event)
            po=num2cell(app.PoEditField.Value);
            fp1=app.FlatpackMcCheckBox.Value;
            fp2=app.FlatpackCoyCheckBox.Value;
            fp3=app.FlatpackRGCheckBox.Value;
            if fp1==1
                fpp=[app.fpmc];
            else
                fpp=0; % want to leave it blank;
            end 
            if fp2==1
                fpp=[app.fpcoy];
            else
                fpp=0;
            end
            if fp3==1
                fpp=[app.fprg];
            else
                fpp=0;
            end
            app.PoTextArea.Value=[string(po)];
            app.ProductTextArea.Value=[string(fpp)];

Answer 1

[Aghamarsh Varanasi]

Hi,

You can use string array to achieve this functionality. For reference, you can use the following code snippet

function DoneButton_4Pushed(app, event)
    fpp = strings(1,3);
    c = 0;
    
    % if the 'app.FlatpackMcCheckBox.Value' is false, fpp(1) is left empty
    if app.FlatpackMcCheckBox.Value 
        fpp(c+1) =  app.fpmc;
        c = c + 1;
    end 
    
    if app.FlatpackCoyCheckBox.Value
        fpp(c+1) = app.fpcoy;
        c = c + 1;
    end
    
    if app.FlatpackRGCheckBox.Value
        fpp(c+1) = app.fprg;
        c = c + 1;
    end
    app.ProductTextArea.Value= fpp ;
end

Hope this helps

[Walter Roberson]

I am not clear what class() app.fpmc is ?

[Joseph Catanese]

It is ‘flatpack mc’ In properties

[Joseph Catanese]

@Aghamarsh Varanasi Thank you this worked amazingly exactly what i wanted can i do this with numbers too though because i tried the same method and it overwrites the number

[Walter Roberson]

flatpack mc is not a valid class name in MATLAB.

isfloat(app.fpmc)
isinteger(app.fpmc)
ischar(app.fpmc)
isstring(app.fpmc)
ishandle(app.fpmc)
isobject(app.fpmc)

[Aghamarsh Varanasi]

Hi Walter, app.fpmc seems to be a placeholder for the strings that we are trying to display in the text area. eg. app.fpmc = "Flatpack mc";

[Walter Roberson]

 fpp(c+1) =  app.fpmc;

would fail if app.fpmc were a character vector.

[Aghamarsh Varanasi]

Hi Joseph, you can do that same with integers, but you need to convert the integers to strings inorder to assign it to TextArea.

[Joseph Catanese]

so num2str?

with the numbers i have it as a variable entered rather then just numbers.

the numbers are matrixs too and i tried using mat2str but i dont know

fpmct =[fpqt1/ttfp1,fpqt1/ttfp2,fpqt1/ttfp3]'
time=strings(1,6)
t=0;
t(t+1)=string(mat2str(fpcoyt/60,2));
app.TimeTextArea.Value=time;

error msg

Unable to perform assignment because the left and right sides have a different number of elements.

[Walter Roberson]

t=0;

That creates t as a scalar numeric value

t(t+1)=string(mat2str(fpcoyt/60,2));

t has scalar numeric value 0, so t(t+1) is t(1) and identifies a scalar numeric output location.

The right hand side, on the other hand, is a string object or string array. mat2str() returns a character vector n matter what the shape of the input is, so string() of that would be a string scalar. Then because the result is being assigned into a numeric scalar, the string() class will attempt to convert the string scalar to numeric.

Now, if you use mat2str() with a scalar numeric value, then the result will be the scalar numeric value as a character vector, without any "decoration". For example, mat2str(5) is going to give you '5', not '[5]' . And it so happens that if you assign a string scalar has has the form of a scalar number, in a context that needs a double, then the string() class will do the equivalent of str2double() [except faster!!] . The numeric value that would end in in t(1) would, in that case, be the same scalar numeric value as was input, except possibly rounded.

If you use mat2str() with something that is not a scalar numeric value, then the result will have decorations, such as mat2str(4:5) giving the result '[4 5]' . And when the string() class tries to convert that to double to store into t(1) then the result you would get in t(1) would be NaN.

Meanwhile, you created the variable time as a 1 x 6 string array, each empty strings, and that string array is what you assign to the Value, even though you did not store anything into it. But you ignore the numeric value that you stored into t(1) after you put it there.