random number generation for known sum

i what do generate some 15 random numbers that sum for each separate value of say, 60 , 70, 40, 65. How would i go abouts this?
sum = [60 70 40 65];
n=15;
b = [ ];
for i = 1:1:n,
a = randi([1,??]);
b = [b a];
end

 Accepted Answer

n=60;
m=1:n;
a=m(sort(randperm(60,15)));
b=diff(a);
b(end+1)=60-sum(b)
sum(b)

13 Comments

thanks Azzi, i get an error
Error in ==> Untitled at 3
a=m(sort(randperm(60,15)));
You must be using an older MATLAB that does not have that enhancement to randperm(). Try
t = randperm(n);
a=m(sort(t(1:15));
I want to generate the same, but I need Non-integer numbers. Is it possible?
@Arnab
sumtarget = 60;
n = 5;
x = diff([0,sort(randperm(sumtarget+n-1,n-1)),sumtarget+n])-1
Arnab Pal
Arnab Pal on 4 Nov 2018
Edited: Arnab Pal on 4 Nov 2018
Sir, It is generating the integer numbers only.
Ah sorry some how I read non-negative.
For random non-negative floating numbers, you need using Roger Stafford FEX
Is there an easy way to control the maximum value each number in 'b' can have? Say, each value in 'b' must be less than or equal to 7, and still the 15 numbers in 'b' should add up to 60.
Roger's FEX contribution, the a and b parameters are lower bound and upper bound. You can use zeros for the lower bound if that is appropriate for your situation.
Tejas
Tejas on 13 Jul 2020
Edited: Tejas on 13 Jul 2020
I want the numbers to be integers, as in the original question. Roger's FEX contribution seems to work with real numbers.
The easiest way is perhaps using Roger FEX function, then do some sort of "integering" the float solution
sumatarget = 60
n = 15;
ub = 7;
x = floor([0; cumsum(randfixedsum(n,1,sumatarget,0,ub))]);
x(end) = sumatarget; % prevent floating point error
r = diff(x)
The distribution might be not perfectly uniform but possibly close enough and suitable for what ever you want to do with it.
Integering the solution from Roger's function works very well for me. I do not require the numbers to be perfectly uniform. Thanks!

Sign in to comment.

Categories

Tags

Asked:

on 27 Aug 2013

Commented:

on 14 Jul 2020

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!