arrange equation results from min to max to use after

t = [2993;3975.9;5063;6150;6919;8192.7;8862;10240.9;11488;12409.63;13545]
f = @(t) (2.2/9500).*((t/9500).^1.2).*exp(-((t/9500).^2.2))
g = @(t) 1-exp(-((t/9500).^2.2))
i want f(t) to be arranged from min to max to then do f(t)-g(t)
0.32398874
answers should be 0.39063829
0.31369048
0.31787694
....
...

 Accepted Answer

t = [2993;3975.9;5063;6150;6919;8192.7;8862;10240.9;11488;12409.63;13545]
t = 11×1
1.0e+04 * 0.2993 0.3976 0.5063 0.6150 0.6919 0.8193 0.8862 1.0241 1.1488 1.2410
f = @(t) (2.2/9500).*((t/9500).^1.2).*exp(-((t/9500).^2.2))
f = function_handle with value:
@(t)(2.2/9500).*((t/9500).^1.2).*exp(-((t/9500).^2.2))
g = @(t) 1-exp(-((t/9500).^2.2))
g = function_handle with value:
@(t)1-exp(-((t/9500).^2.2))
sort(f(t))-g(t)
ans = 11×1
-0.0757 -0.1368 -0.2215 -0.3189 -0.3921 -0.5142 -0.5760 -0.6925 -0.7810 -0.8346

5 Comments

that's the problem the result is wrong
0.32398874
result should be like this 0.39063829
0.31369048
0.31787694
.......
....
...
Do you want to display in 8 digit format? If I am right you can do as
t = [2993;3975.9;5063;6150;6919;8192.7;8862;10240.9;11488;12409.63;13545]
t = 11×1
1.0e+04 * 0.2993 0.3976 0.5063 0.6150 0.6919 0.8193 0.8862 1.0241 1.1488 1.2410
f = @(t) (2.2/9500).*((t/9500).^1.2).*exp(-((t/9500).^2.2))
f = function_handle with value:
@(t)(2.2/9500).*((t/9500).^1.2).*exp(-((t/9500).^2.2))
g = @(t) 1-exp(-((t/9500).^2.2))
g = function_handle with value:
@(t)1-exp(-((t/9500).^2.2))
printing = @(x)fprintf('%0.8f\n', x);
printing(sort(f(t))-g(t))
-0.07572129 -0.13678446 -0.22148910 -0.31892662 -0.39209702 -0.51415077 -0.57598195 -0.69252235 -0.78096654 -0.83461035 -0.88712616
the problem is that these results are wrong
those are the correct answers
my bad i forgot that f(t) is * 10^-4 so thank you very much for helping me arranging my equation results

Sign in to comment.

More Answers (0)

Categories

Find more on Programming in Help Center and File Exchange

Products

Release

R2012a

Tags

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!