A question about product operation

Hello all!
I'm not sure if this was explained before, but I could not find any answer to this.
So, if i have x=[a b c] and y=[d e f] I'd like to know (if it's possible) how I could obtain:
.
z=
h i j
k l m
n o p
where:
h=a*d k=a*e n=a*f
i=b*d l=b*e o=b*f
j=c*d m=c*e p=c*f
Thanks!

 Accepted Answer

Jan
Jan on 16 Sep 2013
Edited: Jan on 16 Sep 2013
x = [1, 2, 3]
y = [10, 20, 30]
z = x' * y
The matrix multiplication of a column vector with a row vector replies the dyadic product. x*y' would reply the dot-product.
Slower alternative:
z = bsxfun(@times, x', y)

6 Comments

Thank you!
Beaten by 1 minute ... ;-)
Could you tell me how i could implement this in Simulink?
I put two constant blocks (one with x and one with y) and i put a product block. At the output of X, before connecting to the first input of the product i have to put a transpose block. I've tried "Transpose" and "Reshape" blocks but they didn't do the job. (the result it's not a 3x3 matrix) I also tried to use the blocks from the "User-defined functions" but I did not succeed.
Yes, if i make a .m file or simply type in command line z=x'*y it works (i have a 3x3 vector in workspace called z).
Any idea how this can be done in Simulink?
As described in the documentation, you can set the product block to "Matrix Mode". I've never worked with Simulink, but Google showed me this information after a few seconds of searching. Does it help already?
Of course you could also put this inside of a MATLAB function block.
Dan p wrote:
I also tried to use the blocks from the "User-defined functions" but I did not succeed.
Please show us, what you have tried and explain "did not succeed" with details.

Sign in to comment.

More Answers (1)

Simon
Simon on 16 Sep 2013
Edited: Simon on 16 Sep 2013
Hi!
x = [1, 2, 3]; % row vector
y = [2; 3; 4]; % column vector
z = y * x;

Categories

Find more on Modeling in Help Center and File Exchange

Asked:

on 16 Sep 2013

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!