Is there a function that retrieves the filename of the current script?

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Is there a way to, from a .m file, determine the filename (including directory path) of that .m file?

Accepted Answer

Walter Roberson
Walter Roberson on 20 Jun 2011
S = dbstack();
S(1).file
You might have to use the -completenames option.
  5 Comments
Kevin  Hartman
Kevin Hartman on 13 Mar 2021
Additionally, S(1).name in the above example returns the filename sans extension c. MATLAB 2020b

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More Answers (3)

Kaustubha Govind
Kaustubha Govind on 20 Jun 2011
p = mfilename('fullpath')
  3 Comments
Walter Roberson
Walter Roberson on 20 Jun 2011
mfilename does not include the extension, and thus cannot distinguish between .p and .m files.
mfilename without any option does not include the path as was specifically requested by the user.

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Eric LePage
Eric LePage on 23 Oct 2019
I'd appreciate a qualification, because what I get for R2019b is not very helpful; it certainly isn't the name of the currently running mfile. Thanks.
P = mfilename
P =
'LiveEditorEvaluationHelperESectionEval67edf31d'
or
S = dbstack();
>> S(1).file
ans =
'LiveEditorEvaluationHelperESectionEval67edf31d.mlx'
  8 Comments
Rik
Rik on 24 Oct 2022
@Chris Jennings You can strip the path away with the fileparts function:
[FullPath,Filename,ext]=fileparts(matlab.desktop.editor.getActiveFilename)

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Martin Koch
Martin Koch on 23 Oct 2022
With the Path class you can get the file path with
Path.this
and the parent directory with
Path.here
Use the string method to convert to a string if needed:
Path.this.string
Disclaimer: I'm the author.

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