Given the square root of a square number, seed, and a range, n, find the square number, Z as well as the other side, y, the square root of a square number i.e. return the hypotenuse squared as well as the length of the other side. Note that n is the number of squares to search through starting with one.
HINT: Z = seed^2 + y^2 where Z = z^2, find Z first and then y.
Note that Z, seed^2 and y^2 are all perfect squares.
>> [z s] = findPerfectZ(3,6)
z = 25
s = 4
>>
Solution Stats
Problem Comments
Solution Comments
Show commentsProblem Recent Solvers61
Suggested Problems
-
287 Solvers
-
Find the maximum number of decimal places in a set of numbers
3610 Solvers
-
Create a matrix X, where each column is a shifted copy of the vector v
228 Solvers
-
Find Index of maximum Value and maximum Value of a vector
173 Solvers
-
Convert a Cell Array into an Array
2345 Solvers
More from this Author16
Problem Tags
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!
There's a problem with the solution suite. For seed=12 and n=16, the proposed answer of 5, 12, 13 as a Pythagorean triple is indeed a good one. However, 9, 12, 15 is equally valid but not included as an answer. To avoid this, I would suggest changing the problem so that it requires finding the answer with the minimum Z^2 to avoid ambiguity.