Problem 313. Pythagorean perfect squares: find the square of the hypotenuse and the length of the other side

Created by Bruce Raine

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Last Solution submitted on Dec 31, 2020

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Peter Wittenberg on 2 Jan 2014

There's a problem with the solution suite. For seed=12 and n=16, the proposed answer of 5, 12, 13 as a Pythagorean triple is indeed a good one. However, 9, 12, 15 is equally valid but not included as an answer. To avoid this, I would suggest changing the problem so that it requires finding the answer with the minimum Z^2 to avoid ambiguity.

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Problem 313. Pythagorean perfect squares: find the square of the hypotenuse and the length of the other side

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Problem 313. Pythagorean perfect squares: find the square of the hypotenuse and the length of the other side

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