Could you be more specific on the underlying relationship between the input (timetable) and output (mean duration)? That is, among which group are you calculating the mean duration? From your example, there are only 2 groups of destinations, i.e., BOS and NYC, but why there are 3 values in the output? What's the mapping behind? Also, your problems including Part 1, 4, 5 are all based on single test, which allows hard-coded solution to lead.
Peng do share the grouping method cause it eludes me :)
There seems to be an error with the test suite: the first mean time should be 03:09:50 and not 03:09:05. And the test code should probably be abs(ttDur - Dur) <= duration([0 0 1]) (not 0.01).
This is not a solution. It returns just a single value instead of 3 and somehow works.
Eventually figured out the grouping method in this problem, which is not so obvious...
This is a proper solution and with small size.
Make a checkerboard matrix
Remove any row in which a NaN appears
Calculate area of sector
String Array Basics, Part 2: Convert String Array to Cell Array; No Missing Values
Extra safe primes
Use a timetable to analyze a train timetable (Part 3)
Use a timetable to analyze a train timetable (Part 2)
Use a timetable to analyze a train timetable (Part 5)
Use a timetable to analyze a train timetable (Part 1)
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