Problem 44370. Octoberfest festival
A group of students decided to visit Octoberfest festival. First they ordered one beer, then after halfhour they taken one more, after one more halfhour they ordered two more beers like sum of previous two times. Then after having spend a good time and anoter half an hour they ordered three beers. The situation went on. Task: calculate how many beers they ordered after n halfhours for given n  number of halfhours.
Example:
n=1 result will be 2;
n=2 result will be 4.
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6 Comments
The problem is so badly stated that we have to guess what we have to do...
Agreed..
I can not use some functions from Symbolic Math Toolbox here! What should I do to fix it?
"Solved" problem with trivial ifelse solution for all cases. The problem doesn't stated correctly. OR test cases error.
P.S. Where is dislike button>
The problem and test cases are consistent.
At time zero they order one beer. After 30 minutes they order one more beer. So, within half an hour they've ordered two beers.
After another 30 minutes they order the sum of the previous two orders, which is two beers (1+1=2). So, within two halfhours they've ordered four beers. After yet another 30 minutes they again order the sum of the previous two orders, which is now three beers (1+2=3). So, within three halfhours they've ordered seven beers. And they continue on, thenceforth always ordering the sum of the preceding two orders. For example, the following order would be five beers (2+3=5), so the cumulative total after four halfhours would be twelve beers.
This is a very famous sequence, albeit in a different context.
(It would have been better to have more text cases, though.)
Good problem, but you could add more test cases, like n = 0, which should be 1. And a higher n, 144, which should be much greater than 2 billion beers (after 3 days straight at Octoberfest, wow). Unfortunately, It is impossible to calculate the beer for all 16 to 18 days within machine precision.
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