Riemann sum is a certain kind of approximation of an integral by a finite sum.
In this problem, I want you to use Midpoint Riemann sum to integrate a function.
As a test case, we should know that the integral of cos(x) over the interval [0,pi/2] is 1. Code numerical code, has only known spacing of the interval:
dx = pi/10;
x=0:dx:pi/2;
fx = cos(x([1:end-1])+dx/2)
riemannInt(fx,deltax)
ans =
1.004124203953987
Round the answer according to the test suite
Solve

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Last Solution submitted on Mar 02, 2026

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George Berken Riccardo G. Gengyue Lorenzo

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