Saranika Das
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double summation. for loop
N = 16; h=1/N; b=(2/(N*200))^0.5; c=(250000*h/(N*200))^0.5; L=1; xt=7/N; syms xp m n Fi=-((h*(b^2)/(c^2))^2)*(cos((2*m-...
3 years ago | 0 answers | 0