Community Profile

photo

Jan Filip


Last seen: 8 months ago Active since 2020

Statistics

All
  • Thankful Level 2
  • Thankful Level 1
  • Solver

View badges

Content Feed

View by

Question


Index exceeds the number of array elements in ODE using anonymous function
I dont't understand what is wrong with this scirpt. For different set of equations I was able to use anonymous functions inside ...

12 months ago | 1 answer | 0

1

answer

Question


How to plot coordinate data to appear solid with lighting effect?
I have quite delicate problem. In the for loop I am plotting these circles using plot3(x,y,z) so after number of iteration...

1 year ago | 2 answers | 0

2

answers

Question


Avoid root switching using roots
Hello, I am having following problem. It is a very simple. First formulate symbolically some matrix . Then I wish to study . ...

1 year ago | 0 answers | 0

0

answers

Question


transform ode15i input to ode15s input
Since I got completely stuck in the last two weeks I am giving up with ode15i solver and I would like to solve my equations usin...

1 year ago | 0 answers | 0

0

answers

Question


Piecewise ode15i
Suppose that given DAE system containing peicewise defined function. What is more convenient way to call ode15i: a) put condit...

1 year ago | 1 answer | 0

1

answer

Question


ode15i instability and initial values
Consider following MWE: eqn1 = i_V11(t) + u_1(t)/10 - u_2(t)/10 == 0 eqn2 = (3*u_2(t))/25 - u_1(t)/10 - u_3(t)/50 + (77371252...

1 year ago | 0 answers | 0

0

answers

Question


Generation of symbolic vector of functions
I need to define a lot of symbolic variables for DAE solver. Instead of using sym f1(t) f2(t) % up to arbitrary fN(t) i woul...

1 year ago | 1 answer | 0

1

answer

Solved


Times 2 - START HERE
Try out this test problem first. Given the variable x as your input, multiply it by two and put the result in y. Examples:...

2 years ago

Question


Gegenbauer polynomials wont produce Chebyshev polynomials using Symbolic Toolbox
Consider code syms x n = 4; a = -0.5; gegenbauerC(n,a,x) It produces following output - (5*x^4)/8 + (3*x^2)/4 - 1/8 which...

2 years ago | 1 answer | 0

1

answer