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请问这个复杂的三角函数怎么定义函数。
少了个乘号 另外角度值求三角函数要用cosd代替cos，其他同理 f=@(x) acosd((cosd(x)-cosd(20+x)+2*cosd(x)*cosd(20+x))/(cosd(x)+cosd(20+x)));
3 years ago | 0
| accepted
错误使用 solve>getEqns (line 418) List of equations must not be empty. 出错 solve (line 226) [eqns,vars,options] = getEqns(varargin{:});。
用两个等号连接方程两端 根据版本用 solve('a*x^2+b*x+c==0','x') 或者在较新版本里面用 solve([a*x^2+b*x+c==0],[x]) 得到 ans = -(b + (b^2 - 4*a*c)^(1/2))/...
3 years ago | 0
