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Question
i need code in matlab
(x-a)^2+(y-b)^2=r^2 ,,, the point (a,b) center of circle and (r) the radius .. with point (-1,3.2) --- (-8,4)--- (-6.5,-9.3) ...
3 years ago | 2 answers | 0
2
answersQuestion
What is wrong here? The equation of a circle given its center
syms x;syms y;syms R e1=(x+1)^2+(y-3.2)^2==R^2; e2=(x+8)^2+(y-4)^2==R^2; e3=(x+6.5)^2+(y+9.3)^2==R^2; result=solve(e1,e2,e3)...
3 years ago | 1 answer | 0
