Simplify Matrix decimal to integers

I do not want
881/2158 985/1393 780/1351
881/2158 -985/1393 780/1351
-881/1079 0 780/1351
But I want
1 1 1
1 -1 1
-2 0 1
How do I do this using one single function ?
I get this error if I use simplify
Check for incorrect argument data type or missing argument in call to function 'simplify'.

Answers (2)

One way is
M = [881/2158 985/1393 780/1351
881/2158 -985/1393 780/1351
-881/1079 0 780/1351]
M = 3×3
0.4082 0.7071 0.5774 0.4082 -0.7071 0.5774 -0.8165 0 0.5774
ip = find(M>=0);
in = find(M<0);
M(ip) = ceil(M(ip));
M(in) = floor(M(in));
disp(M)
1 1 1 1 -1 1 -1 0 1
Don't know where you got the -2 from though!

1 Comment

I don't want to round the numbers ... I need to simplify it like 881/2158 is common factor in column 1 ... 985/1393 in column 2 ... 780/1351 in column 3

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Cris LaPierre
Cris LaPierre on 19 Oct 2021
Edited: Cris LaPierre on 19 Oct 2021
It's likely going to take two functions: one to convert your symbolic expressions to numeric, and a second to round.
I would probably do something like
new_var = round(double(old_var))

5 Comments

I don't want to round the numbers ... I need to simplify it like 881/2158 is common factor in column 1 ... 985/1393 in column 2 ... 780/1351 in column 3
You say you are getting an error message, so you must have code already. Please share what you have tried.
Do you mean to do something like this? If so, look into elementwise division.
M = [881/2158 985/1393 780/1351
881/2158 -985/1393 780/1351
-881/1079 0 780/1351];
B = M./M(1,:)
B = 3×3
1 1 1 1 -1 1 -2 0 1
Or you could normalize by the first element in each column.
M = [881/2158 985/1393 780/1351
881/2158 -985/1393 780/1351
-881/1079 0 780/1351];
B = normalize(M, 1, 'scale', 'first') % Normalize in dimension 1
B = 3×3
1 1 1 1 -1 1 -2 0 1
Thanks But now we know M but what if we need to normalize it when M is not known

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Release

R2021b

Asked:

on 19 Oct 2021

Edited:

on 22 Oct 2021

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