how to apply pso to formula

i want to apply pso to function y = -0.0429x4 + 1.1527x3 - 11.178x2 + 43.153x + 19.63

Answer 1

[Star Strider]

The parameters have to be elements of a vector (and the appropriate operators must be provided, in this instance multiplication) —

y = @(x) -0.0429*x(4) + 1.1527*x(3) - 11.178*x(2) + 43.153*x(1) + 19.63 

If the posted equation is actually something different, (such that ‘x4’ is actually ) those details — and a clear explanation of the actual problem — need to be provided. See the documentation on Anonymous Functions for details on them.

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[kyungdoo lee]

Are you saying the question has errors like vector parameters?

[Star Strider]

If the parameters to be optimised are ‘x’, they must be elements of a vector.

That is how the optimisation functions work.

Also, it is necessary to be clear about the objective of the optimisation.

For example —

y = @(x) -0.0429*x(4) + 1.1527*x(3) - 11.178*x(2) + 43.153*x(1) + 19.63;
x0 = rand(4,1);
[xe1,fval] = fminsearch(y, x0)                                   % Absolute Minimum

 
Exiting: Maximum number of function evaluations has been exceeded
         - increase MaxFunEvals option.
         Current function value: -4553455067893434311976313508498416664992637329080320.000000 

xe1 = 4×1

1.0e+49 * -8.3765 8.4337 0.3630 0.4905

fval = -4.5535e+51

fprintf('%23.15E\n',xe1)

 -8.376509228679389E+49
  8.433651206800148E+49
  3.629666932350592E+48
  4.905026065674677E+48

[xe2,fval] = fminsearch(@(x)norm(y(x)), x0)                     % Mean Square Minimum

xe2 = 4×1

-0.1648 1.1516 0.3351 0.7555

fval = 8.3061e-05

fprintf('%23.15E\n',xe2)

 -1.647817685875986E-01
  1.151648047524384E+00
  3.351060012819946E-01
  7.554828255085815E-01

Experiment to get the desired result.

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