Number of rows based on frequency of one integer and position of another integer
3 views (last 30 days)
Show older comments
Hello. I was wondering if someone could help me with this:
Let's say you have a 2000 x 2 matrix, where all the elements are integers. How can we count the number of rows that contain the number 10 in its first column and any number with the highest 5 integers in the second column?
In other words, the following but where X is the fifth highest number in the second column:
nnz(matrix(:,1) == 10 & matrix(:,2) > X);
EDIT -> Very importantly, the list with the highest 5 integers must be determined for each integer in the first column. So, if one wanted to do this for the number 10, it must be determining the highest 5 integers in the second column WHEN the integer in the first column is 10.
Thanks!
0 Comments
Accepted Answer
Voss
on 17 Jan 2022
Get the set of unique numbers in the 2nd column:
col2_vals = unique(matrix(:,2));
The 5th highest is 4th from the end. So, to match any number within the highest 5:
nnz(matrix(:,1) == 10 & matrix(:,2) >= col2_vals(end-4));
4 Comments
Voss
on 18 Jan 2022
idx = matrix(:,1) == 10;
col2_vals = unique(matrix(idx,2)); % now: unique values of column 2 where column 1 is 10
nnz(matrix(idx,2) >= col2_vals(end-4));
More Answers (1)
David Hill
on 17 Jan 2022
r=unique(matrix(:,2));
r=r(end-4:end);
n=nnz(matrix(:,1)==10&ismember(matrix(:,2),r));
3 Comments
David Hill
on 18 Jan 2022
r=unique(matrix(matrix(:,1)==10,2));
r=r(end-4:end);
n=nnz(matrix(:,1)==10&ismember(matrix(:,2),r));
See Also
Categories
Find more on Matrix Indexing in Help Center and File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!