angle and abs function gives me 'Subscript indices must either be real positive integers or logicals.' error
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youssef Mostafa
on 18 Apr 2022
Commented: John D'Errico
on 19 Apr 2022
if strcmp(app.Type_of_analysis.Value,'Exact') && app.Primary.Value == 1
R2_= app.R2.Value*(app.Turns_ratio.Value)^2;
X2_double=str2double (app.X2.Value);
X1_double=str2double(app.X1.Value);
Xm_double=str2double(app.Xm.Value);
X2_=X2_double*(app.Turns_ratio.Value)^2;
V2_=app.Load_voltage.Value*(app.Turns_ratio.Value)^2;
angle= -acosd(app.Power_factor.Value);
Power1= app.Input_Power.Value*app.Percentage_of_loading.Value*0.01;
I_load_magnitude=Power1/V2_;
I_load_= I_load_magnitude*cos(angle*pi/180)+I_load_magnitude*sin(angle*pi/180)*1i;
V_x= V2_+I_load_*(R2_+X2_double);
I_m= V_x/Xm_double;
I_c= V_x/app.Rc.Value;
I_phi= I_m+I_c;
I_input= I_phi+I_load_;
I_input_angle= angle(I_input); ****Error*****
I_input_magnitude= abs(I_input); ****Error*****
Input_voltage= V_x+I_input*(app.R1+X1_double);
app.Input_voltage_magnitude= abs(Input_voltage);
app.Input_voltage_angle= angle(Input_voltage);
Power_factor1= cos(angle(Input_voltage)-I_input_angle);
app.Input_Power.Value=app.Input_voltage_magnitude*I_input_magnitude*Power_factor1;
app.Voltage_regulation.Value=(app.Input_voltage_magnitude-V2_)/V2_*100;
end
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Accepted Answer
Star Strider
on 19 Apr 2022
First the code defines:
angle= -acosd(app.Power_factor.Value);
then later it calls the angle function:
I_input_angle= angle(I_input); ****Error*****
and MATLAB now firmly believes that angle is a variable and not a function because that is what you told it earlier.
The solution is to re-name the ‘angle’ variable to something that does not overshadow the angle function and means something in context, for example ‘pf_angle’.
I do not see that anything is assigned to a variable ‘abs’, however I suspect something similar was done somewhere else in the code. The solution is similar.
.
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More Answers (1)
Voss
on 18 Apr 2022
Do you have a variable called abs? To find out, do:
whos abs
If there is one, clear it by doing:
clear abs
This will clear the variable abs from your workspace, allowing you to run the function abs.
2 Comments
John D'Errico
on 19 Apr 2022
You don't understand. This error essentially indicates you have done exactly that. For example, we see this line of code:
angle= -acosd(app.Power_factor.Value);
So you did create a variable named angle. Then you try to use the function angle.
I_input_angle= angle(I_input); ****Error*****
However, this fragment of code is only part of what you have written. Somewhere in that code, you have defined a variable named abs.
DON'T DO THAT!
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