for loop for two particular days of a week

Hi,

I am trying to make a for loop counting each monday and thursay for some period of time like one year. I want to start with coming Monday, 08/08/2022 counting it as 1 then Thursday 4, next monday 8, next Thursday 11 and upto a total of 100 Monday plus Thursday.

The vector looks like this V=[1 4 8 11 ......................]. It is going to be inconvinent to write all elements of this vector if a long period of time like 2 years choosen. I am trying to use a for loop and generalize above vector.

Any suggestions will be highly apperciated.

Thanks

Dharma

Answer 1

[sudobash]

Hi!

As per my understanding, you want to create a vector of the following sequence: 1, 4, 8, 11, 15, 18,...

This is how you could do it using a while loop:

vec = [1];
while length(vec) < 100
    % Check if previous element was Monday
    if mod(length(vec),2) == 1
        % Add 3 to last element to get Thursday
        vec = [vec vec(end)+3];
    else
        % Add 4 to last element to get back Monday
        vec = [vec vec(end)+4];
    end
end

vec

vec = 1×100

1 4 8 11 15 18 22 25 29 32 36 39 43 46 50 53 57 60 64 67 71 74 78 81 85 88 92 95 99 102

Hope this solves your problem.

[Dharma Khatiwada]

Thank you!

I just have one more question.

I need to write a for loop below vector 'vec' such that loop picks only for the element of 'vec'.

For example, for i=1, 4, 8, 11, 15, ...........

c2(i)=...............

Could you please help me?

Dharma

Answer 2

[Voss]

n_weeks = 50;
vec = reshape((0:n_weeks-1)*7+[1;4],1,[]);

[Dharma Khatiwada]

Thank you!

It worked perfectly.