Limiting range of a matrix

I have matrix A = [1 2 3 4 5 6 7 8];

I try to limit the matrix to numbers greater than 3 and less than 6 how do I do it ?

I use this line but it assigns numbers less then 3 to 3 and numbers greater then six to six. Instead i want to eliminate those numbers in matrix which dont belong in this range.

max(min(A,3),6)

Answer 1

[Karim]

You can use logical indexing to obtain such a result, see below for a demonstration

A = [1 2 3 4 5 6 7 8];

% define the limits
maxValue = 6;
minValue = 3;

% use logic to find the indexes
idx = A >= maxValue | A <= minValue;

% set the values we don't want to zero
A(idx) = 0

A = 1×8

0 0 0 4 5 0 0 0

it is off course also possible to do this in a single line:

A = [1 2 3 4 5 6 7 8];
A(A>=6 | A<=3) = 0

A = 1×8

0 0 0 4 5 0 0 0

[Kamil Kacer]

Thank you but also how do I put zeros instead of numbers there are out of range ?

[Karim]

ah that is not a problem, i will adjust the answer

[Kamil Kacer]

Thank you so much <3

[Kamil Kacer]

But it doesnt really work for my array c I tried this code but it gives me some weird matrix

 cl{m} = c{m}(c{m}>=0.5 | c{m} <= 0.05) ==0;

[Walter Roberson]

 c{m}(c{m}>=0.5 | c{m} <= 0.05) = 0;

[Voss]

 cl{m} = c{m}(c{m}>=0.5 | c{m} <= 0.05) ==0;

That's not assigning elements of c{m} to 0; it's comparing certain elements of c{m} to 0, then storing the result (of class logical, i.e., true/false) in cl{m}.

That's a very different operation than what you asked about and got answers for.

[DGM]

Note that zero is also an out-of-range value, so filling the elements with zero doesn't solve the problem of limiting the range of the array.

When someone asks "I want to arbitrarily remove elements from an array" one has to ask what "remove" means, because it's not obvious. You can't just remove any element from an array and retain the shape of the array. If you want to fill the missing elements with some value, the value that you use depends entirely on your needs and the class of the array. So what exactly are your expectations?

Answer 2

[Torsten]

A = [1 2 3 4 5 6 7 8];
A(A<3) = 3;
A(A>6) = 6;
A

A = 1×8

3 3 3 4 5 6 6 6